nektarin12
nektarin12
12-10-2016
Chemistry
contestada
Fe2O3+2Al ~2Fe+Al2O3
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Аноним
Аноним
12-10-2016
I presume that you mean 15.0 g of iron(III) oxide
moles Fe2O3 = 15.0 g /159.694 g/mol= 0.0939
the ratio between Fe2O3 and Al2O3 is 1 : 1
moles Al2O3 = 0.0939
mass Al2O3 = 0.0939 mol x 101.963 g/mol= 9.57 g
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