Answer:
B. Bending her knees will make the force 20 times smaller.
Explanation:
By the Impulse Theorem, we notice that the normal force from the ground to the gymnast counteract the intial linear momentum of the gymnast during a certain time until rest is reached. The impulse ([tex]Imp[/tex]), measured in newton-second, is function of initial linear momentum, measured in kilogram-meters per second, only and, hence, remains constant. That is:
[tex]Imp = m\cdot v[/tex] (1)
Where:
[tex]m[/tex] - Mass of the gymnast, measured in kilograms.
[tex]v[/tex] - Initial speed of the gymnast, measured in meters per second.
If we know that [tex]m = 60\,kg[/tex] and [tex]v = 20\,\frac{m}{s}[/tex], the impulse experimented by the gymnast is:
[tex]Imp = (60\,kg)\cdot\left(12\,\frac{m}{s} \right)[/tex]
[tex]Imp = 720\,\frac{kg\cdot m}{s}[/tex]
If the time of collision is increased by a factor of 20 by bending her knees, then normal force from the ground on the gymnast must be decrased by a factor of 20 in order to keep the impulse constant.
Therefore, the right answer is B.