Respuesta :

tagoddard

Answer:

4-3(2-x) < 10+x

4 -6 +3x< 10 + x

-2 +3x< 10 +x

2x< 12

x<6

VectorFundament120

↣ First we solve the Inequality.

[tex]4-3(2-x)<10+x[/tex]

[tex]4-6+3x<10+x[/tex]     ↣ Distribute -3 in (2-x) for easier in solving.

[tex]3x-2<10+x\\3x-x<10+2\\2x<12\\x<6[/tex]

Thus, the answer is x < 6.

↣ Therefore, the greatest possible Integer value of x is 5.

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