geelove361
contestada

A solution is made
by dissolving
29 g of sodium lithium chloride
in water to a final volume of
202 mL solution.
What is the weightweight % or percent by mass of the somute
percent by mass of the solute?

Respuesta :

maacastrobr

Answer:

99.3%

Explanation:

The percent by mass of the solute can be expressed as:

  • % mass = [tex]\frac{MassSolute}{MassSolute+MassSolvent}[/tex] * 100%

And for this problem:

  • Mass of Solute = Mass of sodium lithium chloride = 29 g
  • Mass of Solvent = Mass of Water

So to calculate the percent by mass first we need to calculate the mass of water, to do so we use its density (1 g/L):

  • 202 mL is equal to (202/1000) 0.202 L.

Density water = mass water / volume

  • 1 g/L = mass water / 0.202 L
  • Mass water = 0.202 g

Now we have all the data required to calculate the % mass:

  • % mass = [tex]\frac{29g}{29g+0.202g}[/tex] * 100 % = 99.3%

Answer: 14.3

Explanation:

Otras preguntas