Answer:
The equation of a line that passes through points (2, - 1) and (3, - 4) is
y = -3x + 5
Step-by-step explanation:
In order to solve this we need to know the following slope formula
[tex]m= \frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
Where m is the slope
Now let (2,-1) be [tex](x_{1} , y_{1} )[/tex], and (3,-4) be [tex](x_{2} , y_{2})[/tex]. So now we do....
[tex]m= \frac{y_{2} - y_{1} }{x_{2} - x_{1} } = \frac{-4 + 1}{3 - 2}= \frac{-3}{1} = - 3[/tex]
From here we can find the equation of this line by using the slope point form of an equation, and we will obtain the following......
[tex]y - y_{1} = m(x - x_{1} )\\y + 1 = -3(x -2)\\y + 1= -3x + 6\\y = -3x + 5[/tex]
