contestada

A gas has 1.2 L of volume, 1.8 atm of pressure and 264 K temperature. If both the
volume was doubled but the pressure was halved, what would the new
temperature be?
Your answer

Respuesta :

ardni313

Temperature does not change, remains 264 K

Further explanation

Given

V₁= 1.2 L

P₁ = 1.8 atm

T₁ = 264

Required

The new temperature

Solution

The volume was doubled = 2V₁ = 2 x 1.2 = 2.4 L(V2)

The pressure was halved = 0.5P₁ = 0.5 x 1.8 = 0.9 atm(P2)

Combined gas law :

P₁V₁/T₁=P₂V₂/T₂

Input the value :

[tex]\tt \dfrac{1.8\times 1.2}{264}=\dfrac{0.9\times 2.4}{T_2}\\\\T_2=264[/tex]

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