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The specific heat of water is 4.18 J/gºC. How many Joules of
heat are released to lower the temperature of 150 g water
from 100 °C to 5°C?

Respuesta :

Q = 59565 [J]
Explanation:
In order to calculate the amount of thermal energy needed we must use the following equation.

where:
m = mass = 150 [g]
Cp = 4.18 [J/g*°C]
Tfinal = 5 [°C]
Tinitial = 100 [°C]
Now replacing:

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