Answer:
The length of the transverse axis is 8
Step-by-step explanation:
We have been given the equation of hyperbola
[tex]\frac{(y-2)^2}{16}-\frac{(x+1)^2}{144}=1[/tex]
We can rewrite this equation as
[tex]\frac{(y-2)^2}{4^2}-\frac{(x+1)^2}{12^2}=1[/tex]
Comparing this equation with the standard equation of hyperbola having vertical transverse axis is
[tex]\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1[/tex]
h = -1
k= -2
a = 4
b = 12
The length of the transverse axis is 2a = 2×4 =8
