What is the volume of the following shape?

Answer:
[tex]V=V_{1}+V_{2}=96+36=132\: cm^{3}[/tex]
Step-by-step explanation:
We can divide it into two parts:
First, we can fin the volume of the parallelepiped:
h1 = 16 cm
w1 = 2 cm
d1 = 3 cm
[tex]V_{1}=h_{1}*w_{1}*d_{1}=16*2*3=96\: cm^{3}[/tex]
Now, the volume of the second parallelepiped is:
h2 = (8-2) cm = 6 cm
w2 = 2 cm
d2 = 3 cm
[tex]V_{2}=h_{2}*w_{2}*d_{2}=6*2*3=36\: cm^{3}[/tex]
Finally, the total volume will be the addition of these two volumes.
[tex]V=V_{1}+V_{2}=96+36=132\: cm^{3}[/tex]
I hope it helps you!