Answer:
The probability of getting a 1, 2, 3 on three rolls respectively is [tex]\frac{1}{216}[/tex].
Step-by-step explanation:
Since you are rolling three dies, and each die has six sides, that means there are a total of 216 possible outcomes. Out of the 216 different outcomes, only 1 of them meet the requirement of rolling a '1' on the first die, a '2' on the second die, and a '3' on the third die, so the fraction to represent the situation would be [tex]\frac{1}{216}[/tex].
