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ABC ia an isosceles triangle AB=AC and angle A=53° the length of side, a=12.5cm. Calculate the altitude of the triangle correct to 2s.f.

Respuesta :

Answer:

area of traingle=1/2(sin130×AB×AC)

85×3=sin130×AB×AB

255=76×AB²

255/76=AB²

√332.88=AB

AB=18.24

AC=18.24

Step-by-step explanation:

Hope this helps.

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