A 35 foot ladder is set against the side of the house so it reaches up 21 feet if the ladder at its base and pulls it 4 feet farther from the house how far up the side of the house will the ladder reach now

Respuesta :

Answer:

=14.2

Step-by-step explanation:

a^2 + b^2 = c^2

21 ^2 + x ^2 = 35^2

= 28

28 + 4 = 32

The side with 21 then becomes the new x

x/a =

=14.2

The height of the house that can be ladder reached now will be 14.18 feet.

What is a Pythagoras theorem?

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

A 35-foot ladder is set against the side of the house so it reaches up 21 feet.

Then the base length will be

  35² = 21² + b²

1225 = 441 + b²

   b² = 784

     b = 28 feet

If the ladder is at its base and pulls it 4 feet farther from the house.

Then the height of the house that can be ladder reach now will be

  35² = 32² + h²

1225 = 1024+ h²

   h² = 201

     h = 14.18 feet

More about the Pythagoras theorem link is given below.

https://brainly.com/question/343682

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