makaylah873
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what is the equation, in point-slope form, of the ljne that is perpendicular to the given line and passes through the point (-4,-3)? ​

what is the equation in pointslope form of the ljne that is perpendicular to the given line and passes through the point 43 class=

Respuesta :

Answer:y+3=1/4(x+4)

Step-by-step explanation:

First find the slope of the line with the points -1,1 and 0,-3

1-(-3)/-1-0 = -4

perpendicular is negative reciprocal which is 1/4

now we have the slope, and a point so we can put it in point slope form

y+3=1/4(x+4)

point slope form is y-y1 = m(x-x1)

with x1,y1 being the point and m being the slope

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