Answer:
The total current in the circuit is 0.8 A.
Explanation:
internal resistance of each battery = 2 ohm
Total emf of the circuit, E = E1 + E2 = 2 = 2 = 4 V
Now total internal resistance is
[tex]r = \frac{2\times 2}{2 + 2}= 1 ohm[/tex]
Total resistance, R = 4 = 1 = 5 ohm
Let the current is I.
E = I R
4 = I x 5
I = 0.8 A
