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. f(x) = Square root of quantity x plus nine. ; g(x) = 8x - 13 Find f(g(x)). (1 point)
f(g(x)) = 2 Square root of quantity two x minus one.
f(g(x)) = 8 Square root of quantity x minus four.
f(g(x)) = 2 Square root of quantity two x plus one.
f(g(x)) = 8 Square root of quantity x plus nine - 13

Respuesta :

Answer:

2 sqrt(2x-1)

Step-by-step explanation:

f(x) = sqrt( x+9)

g(x) = 8x-13

f(g(x))

place the function g(x) in for x in f(x)

f(g(x)) = sqrt(8x-13+9)

Combine like terms

f(g(x)) = sqrt(8x-4)

Factor out 4

f(g(x)) = sqrt(4*(2x-1)

           2 sqrt(2x-1)

[tex]\\ \sf\longmapsto f(x)=\sqrt{x+7}[/tex]

[tex]\\ \sf\longmapsto g(x)=8x-11[/tex]

  • g(x) will be put on the place of x

[tex]\\ \sf\longmapsto f(g(x))=\sqrt{8x-11+7}[/tex]

[tex]\\ \sf\longmapsto f(g(x))=\sqrt{8x-4}[/tex]

[tex]\\ \sf\longmapsto f(g(x))=\sqrt{4(2x-1)}[/tex]

[tex]\\ \sf\longmapsto f(g(x))=2\sqrt{2x-1}[/tex]

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