Given the square ABCD with points A(5, 10) and B(-4, 3), the slope of the line segment BC is 7/9
The formula for calculating the slope of a line is expressed as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Given the coordinate point A(5, 10) and B(-4, 3)
Substituting the given coordinate into the formula for slope
[tex]m=\frac{3-10}{-4-5}\\m=\frac{-7}{-9}\\m=\frac{7}{9}[/tex]
Hence the slope of the line segment BC is 7/9
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