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During lunch, Mr. Lee eats a piece of chicken that contains 9 1/9 grams of protein, and Mr. Scott eats a piece of salmon that contains 7 1/7 grams of protein. How much more protein did Mr. Lee eat at lunch?

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Answer:

Mr. Lee ate [tex]1\frac{61}{63}[/tex] more protein than Mr. Scott

Step-by-step explanation:

Find the least common denominator for both fractions.

9: 9, 18, 27, 36, 45, 54, 63

7: 7, 14, 21, 28, 35, 42, 49, 56, 63

Multiply 1/9 by 7/7:

[tex]9 \frac{1}{9} = 9 \frac{7}{56} \\[/tex]

Multiply 1/7 by 9/9:

[tex]7\frac{1}{7} = 7\frac{9}{63}[/tex]

Subtract the two fractions:

[tex]9\frac{7}{63} - 7\frac{9}{63} = 1\frac{61}{63}[/tex]

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