fiera0885
fiera0885
10-12-2021
Chemistry
contestada
How many atoms of copper in 3. 11 g of copper
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Аноним
Аноним
10-12-2021
Atomic weight of copper = 63.5 g
1 mole of copper contains = 63.5g = 6.023 × 10²³ atoms of copper
1 g of copper contains
[tex] = \frac{ 6.023 \times 10²³}{63.5} [/tex]= 9.4 × 10²¹ atoms
Therefore, 3.11g of copper contains
[tex] = 3.11 \times 9.4 \times {10}^{21} \\ [/tex]
= 29.234 × 10²¹ atoms
Hope you could get an idea from here.
Doubt clarification - use comment section.
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