contestada

A 2.1 × 103
kg car accelerates from rest under
the action of two forces. One is a forward
force of 1141 N provided by traction between
the wheels and the road. The other is a 911 N
resistive force due to various frictional forces.
How far must the car travel for its speed to
reach 2.9 m/s?
Answer in units of m.

Respuesta :

MissPhiladelphia
First solve the acceleration of the car using the formula
Fnet = ma Where Fnet is the net force acting on the body M of the object A is the acceleration  
( 1141 – 911) = (2.1 x10^3) a
a = 0.1095 m/s2  

a = v/t
0.1095 = 2.9 /t
t = 26.4783 s  

d = vt
d = ( 2.9 m/s) ( 26.4783 s)
d = 76.7870 m

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