Respuesta :
remember
√-1=i
√(ab)=(√a)(√b)
√-32=
(√-1)(√32)=
(√-1)(√16)(√2)=
(i)(4)(√2)=
4i√2
√-1=i
√(ab)=(√a)(√b)
√-32=
(√-1)(√32)=
(√-1)(√16)(√2)=
(i)(4)(√2)=
4i√2