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An object is thrown upward with an initial velocity of 32.1 m/s. When the object reaches it maximum height, it is true of the acceleration, a, and the velocity, v, that: Group of answer choices

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Answer:

At all times the acceleration a = -9.80 m/s^2   assuming 32.1 is chosen positive

At the top the velocity will be zero because the object is turning around

a = (v2 - v1) / t = -v1 / t since the velocity at the top is zero

t = -v1 / a = -32.1 / -9/8 = 3.26 sec      time to reach top

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