Respuesta :

Answer:

[tex]\sqrt[15]{m^2n^4}[/tex]

Step-by-step explanation:

[tex](\sqrt[5]{m^2n^4} )^{\frac{1}{3}}\\\\\implies( (m^2n^4)^{\frac{1}{5}})^{\frac{1}{3}}\\\\\implies (m^2n^4)^{\frac{1}{5}\times \frac{1}{3}}\\\\\implies (m^2n^4)^{\frac{1}{15}}\\\\\implies (m^2)^{\frac{1}{15}} (n^4)^{\frac{1}{15}}\\\\\implies m^{\frac{2}{15}} n^{\frac{4}{15}}[/tex]

[tex]\sqrt[15]{m^2n^4}[/tex]