The two lines created from the points (0, 10), (2, 7) and (-3, -3) works
exclusively with the three points as presented in the the attached graph.
The possible value in the table obtained from a similar question is presented as follows;
[tex]\begin{array}{|lcl|}(-1, \, 1)&&(2, \, 7)\\(-4, \, 8)&&(2, \, 11)\\(0, \, 10)&&(-3, \, -3)\end{array}\right][/tex]
A line is defined as the shortest distance between two points.
Taking the points (0, 10) and (-3, -3), we have;
[tex]Slope = \dfrac{10 - (-3)}{0 - (-3)} = \dfrac{13}{3}[/tex]
Which gives;
[tex]y -10 = \dfrac{13}{3} \times x[/tex]
[tex]y = \dfrac{13}{3} \cdot x + 10[/tex]
From the attached graph, the points (-1, 1), (2, 7), (2, 11), and (-4, 8) are not on the line.
The linear function, [tex]y = \dfrac{13}{3} \cdot x + 10[/tex] works exclusively for the points (0, 10) and (-3, -3), given that the coordinates of points on the line are; (-1, [tex]5\frac{2}{3}[/tex]), (2, [tex]18\frac{2}{3}[/tex]), (-4, [tex]-7\frac{1}{3}[/tex])
Second line
Taking the points (2, 11) and (-3, -3), we have;
[tex]Slope = \mathbf{\dfrac{11 - (-3)}{2 - (-3)}}= \dfrac{14}{5} = 2.8[/tex]
Which gives;
[tex]y - (-3) = 2.8\times (x - (-3)) = 2.8 \cdot x + 8.4[/tex]
y = 2.8·x + 8.4 - 3 = 2.8·x + 5.4
Which gives;
y = 2.8·x + 5.4
The line, y = 2.8·x + 5.4, works exclusively for the points (2, 11) and (-3, -3), given that the points (2, 7), (2, 11), (0, 10), and (-3, -3) are not on the line
The coordinates of points on the line are; (-1, 2.6), (-4, -5.8), and (0, 5.4).
Learn more about linear functions here:
https://brainly.com/question/20478559
