Hey guys i needed some help on this

Based on the bond energies given, the standard enthalpy of the reaction, ΔH°(rxn) is -296 kJ.
The standard enthalpy change of a reaction is the energy changes involved when substances react under standard conditions to form products.
The standard enthalpy of the reaction, ΔH°(rxn) is calculated as follows:
Sum of energy of bonds broken = 839 + (2 × 413) + (432 × 2) = 2529 kJ
Sum of energy of bonds formed = 347 + (6 × 413) = 2825 kJ
ΔH°(rxn) = (2529 - 2825) kJ
ΔH°(rxn) = -296 kJ
Therefore, the standard enthalpy of the reaction, ΔH°(rxn) is -296 kJ.
Learn more about standard enthalpy at:https://brainly.com/question/25758173