carbon monoxide reacts with iron (ii, iii) oxide (fe3o4) making iron and carbon dioxide. when a student performed the experiment she reacted 70.0 g of fe3o4 with 70.0 g of co and the actual yield of iron was 41.9. calculate the percentage yield.
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pstnonsonjoku pstnonsonjoku · Answer 1 · 2022-04-21T11:08:33+02:00

The percent yiled shows the extent of conversion of reactants to products. The percent yiled here is 83.1%.

The percent yiled in a reaction is calculated as te ratio of the actual yield to the theoretical yiled multiplied by 100.

Hence the balanced reaction equation is; Fe3O4 + 4CO → 3Fe + 4CO2.

Number of moles of Fe3O4 = 70.0 g/232 g/mol = 0.3 moles

Number of moles of CO = 70.0 g/28 g/mol = 2.5 moles

If 1 mole of Fe3O4 reacts with 4 moles of CO

x moles of Fe3O4 reacts with 2.5 moles of CO

x = 0.6 moles

Hence, Fe3O4 is the limiting reactant.

Now;

1 mole of Fe3O4 yileds 3 moles of Fe

0.3 moles of Fe3O4 yileds 0.3 moles * 3 moles/1 mole = 0.9 moles

Mass of Fe produced = 0.9 moles * 56 g/mol = 50.4 g

Percent yield = 41.9 g/ 50.4 g * 100/1 = 83.1%

Learn more about percent yiled: https://brainly.com/question/2862527