The correct answer is: [C]: " [tex]\frac{1}{36}[/tex] " .
Explanation:
We asked to evaluate: " [tex]6^{-2}[/tex] ".
Negative Exponent Rule: x–n = 1/xn.
" [tex]x^{-2} = \frac{1}{x^{2}}[/tex] " ; { x [tex]\neq[/tex] 0}'
So: Plug the number "6" into the variable, "x" :
" [tex]6^{-2} = \frac{1}{6^2}[/tex] " ;
Note the denominator; 6² = 6 * 6 = 36 ;
So: " [tex]\frac{1}^{6^{2}[/tex] "
= " [tex]\frac{1}{36}[/tex] ' ; which corresponds to:
Answer choice: [C]: " [tex]\frac{1}{36}[/tex] "
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Hope this answer—and explanation—is helpful to you
