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Please help!
If a student (represented by initials) was chosen at random, find P(HH|C).
P(HH|C)=2/5


P(HH|C)= 13/16


P(HH|C)=9/16


P(HH|C)=3/5

Please help If a student represented by initials was chosen at random find PHHC PHHC25 PHHC 1316 PHHC916 PHHC35 class=

Respuesta :

Answer:

a.) P(HH|C)=2/5

Explanation:

Given following:

  • P(HH) = 7
  • P(C) = 10
  • P(HH ∩ C) = 4
  • P(HH ∪ C) = 13

Solving steps:

[tex]\sf P(HH|C) = \dfrac{P(HH \cap C) }{P(C)}[/tex]

[tex]\sf P(HH|C) = \dfrac{4 }{10}[/tex]

[tex]\sf P(HH|C) = \dfrac{2 }{5}[/tex]