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Vehicle air bags require that a very specific amount of gas is created so that the gas inflates the airbag without causing it to rupture.
Commonly, this is accomplished by decomposing sodium azide (NaN3) to produce sodium metal and nitrogen gas. How much sodium azide is required to produce 80.0 g of nitrogen gas?

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The amount of sodium azide required will be 123.72 grams

Stoichiometric problem

From the equation of the reaction below:

[tex]2NaN_3 --- > 2Na + 3N_2[/tex]

The mole ratio of sodium azide to nitrogen gas is 2:3

Mole of 80.0 g nitrogen = 80/28.02 = 2.855 moles

Equivalent mole of sodium azide = 2/3 x 2.855 = 1.903 moles

Mass of 1.903 moles sodium azide = 1.903 x 65 = 123.72 grams

More on stoichiometric problems can be found here: https://brainly.com/question/14465605

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