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How much tension must a cable withstand if it is used to accelerate a 1200-kg car vertically upwards at 0.7 m/s^2

Respuesta :

Answer:

M a = T - M g          acceleration of car where T is tension in cable

T = M (g + a) = M (9.80 + .7) = M * 10.5

T = 1200 * 10.5 = 12,600 N

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