we can conclude that yes, the function is periodic with period T = π/2
Is this function periodic or non-periodic?
A function is periodic if for any input X, there exists a value T (where T is the period) such that:
f(x) = f(x + T).
In this particular case, we are told that the period should be π/2, so let's check that.
We can see that:
f(π/4) = 1.2
If we add the period to the argument, we get:
π/4 + π/2 = π/4 + 2π/4 = 3π/4
Now, on the table we can see that:
f(π/4 +π/2 ) = f(3π/4) = 1.2
So at the moment, it seems to be periodic.
Let's try another point.
f(3π/2) = 0.6
If we add the period:
3π/2 + π/2 = 2π
And in the table we can see that:
f( 2π) = 0.6
So we can conclude that yes, the function is periodic with period T = π/2
If you want to learn more about periodic functions:
https://brainly.com/question/6561461
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