Which of the following represents the zeros of f(x) = x3 − 14x2 + 61x − 84? (2 points) 7, 4, −3 7, 4, 3 7, −4, −3 7, −4, 3

f(3) = 3^3 - 14*9 + 61*9 - 84 = 0

so 3 is one zero

long division of the expression by (x - 3) gives the quadratic x^2 -11x + 28 which = (x - 7)(x-4) so the other zeros are 4 and 7.

3,4 and 7

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calculista calculista · Answer 2 · 2018-11-29T00:41:44+01:00

calculista calculista

29-11-2018

Answer:

The zeros of the function are

[tex]7,4,3[/tex]

Step-by-step explanation:

we know that

The x-intercept is the value of x when the value of the function is equal to zero.

The x-intercepts represents the zeros of the function

In this problem we have

[tex]f(x)=x^{3}-14x^{2} +61x-84[/tex]

Using a graphing tool

see the attached figure

The zeros of the function are

[tex]7,4,3[/tex]

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