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A football was kicked vertically upward from a height of 4 feet
with an initial speed of 60 feet per second. The formula
h = 4 + 60t - 16t
2

describes the ball’s height above the ground, h, in feet, t seconds
after it was kicked. Use this formula to solve Exercises 19–20.
19. What was the ball’s height 2 seconds after it was kicked?

Respuesta :

Answer: h=60 feet

Step-by-step explanation:

h=4+60t-16t²

h(2)=4+(60)(2)-(16)(2)²

h(2)=4+120-(16)(2)(2)

h(2)=124-64

h(2)=60 feet

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