The equation in standard form of the circle with radius 8 and center located at (-6 , 3) is (x + 6)^2 + (y - 3)^2 = 64.
The standard form of the equation of circle is given by (x - h)^2 + (y - k)^2 = r^2, where (h , k) is the location of the center and r is the radius of the circle.
Given the radius and center of the circle, substitute these values to the standard form of the equation of the circle.
(x - h)^2 + (y - k)^2 = r^2
where (h , k) = (-6 , 3)
r = 8
(x - -6)^2 + (y - 3)^2 = 8^2
(x + 6)^2 + (y - 3)^2 = 64
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