One of the legs of a right triangle measures 7 cm and the other leg measures 17 cm. Find the measure of the hypotenuse. If necessary round to the nearest tenth.

Answer:
[tex]\huge\boxed{\sf H=18.4\ cm}[/tex]
Step-by-step explanation:
Base = 7 cm
Perpendicular = 17 cm
Hypotenuse = H
[tex](Hypotenuse)^2=(Base)^2+(Perpendicular)^2\\\\(H)^2=(7)^2+(17)^2\\\\(H)^2=49+289\\\\(H)^2=338\\\\Take \ sqrt \ on \ both\ sides\\\\\sqrt{(H)^2} =\sqrt{338} \\\\H=18.4\ cm\\\\\rule[225]{225}{2}[/tex]