Let [tex]N[/tex] be the first of the four odd integers belonging to the sum. The next three integers are [tex]N+2[/tex], [tex]N+4[/tex], and [tex]N+6[/tex].
We then have
[tex]N+(N+2)+(N+4)+(N+6)=4N+12=56\implies 4N=44\implies N=11[/tex]
and so the four integers are 11, 13, 15, and 17.
