Respuesta :
midpoint formula : (x1 + x2) / 2 , (y1 + y2)/2
(8,13)...x1 = 8 and y1 = 13
(10,9)...x2 = 10 and y2 = 9
sub
m = (8 + 10) / 2 , (9 + 13) / 2
m = 18/2 , 22/2
m = (9,11) <==
(8,13)...x1 = 8 and y1 = 13
(10,9)...x2 = 10 and y2 = 9
sub
m = (8 + 10) / 2 , (9 + 13) / 2
m = 18/2 , 22/2
m = (9,11) <==
Answer:
The coordinates of the mid point the line segment whose endpoints are H(8, 13) and K(10, 9) is (9, 11)
Step-by-step explanation:
Given: A line segment whose endpoints are H(8, 13) and K(10, 9)
We have to find the mid point of the line segment whose endpoints are H(8, 13) and K(10, 9).
Consider the given end points H(8, 13) and K(10, 9).
Using Formula for mid point,
[tex]M=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)[/tex]
We have,
[tex]\left(x_1,\:y_1\right)=\left(8,\:13\right),\:\left(x_2,\:y_2\right)=\left(10,\:9\right)[/tex]
Substitute, we have,
[tex]M=\left(\frac{10+8}{2},\:\frac{9+13}{2}\right)[/tex]
Simplify, we have,
[tex]M=\left(9,\:11\right)[/tex]
Thus, The coordinates of the mid point the line segment whose endpoints are H(8, 13) and K(10, 9) is (9, 11)