cdubkythesecond cdubkythesecond

11-08-2017
Mathematics

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A number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and 1. How many solutions are possible for this situation?

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Аноним Аноним

11-08-2017

There are no solutions for this situation. =)

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Аноним Аноним

11-08-2017

we have the 2 equations:-

N = 2n + 3

N = 2(n + 1) or

N = 2n + 2

N cannot be equal to 2n + 3 AND 2n + 2.

Therefore there are no solutions.

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