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A sample of gas with a pressure of 1.33 atm and a temperature of –33˚C has a volume of 10.5 L. What will be the new temperature of the gas if the pressure is increased to 3.11 atm and the volume decreases to 5.6 L?

Respuesta :

Answer:

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Explanation:

P1V1 / T1 = P2V2/T2       Solve for T2

T2 =  T1 / (P1V1) * P2V2    T's must be in Kelvins

T2 = (-33 + 273.15) / (1.33 * 10.5)   *  (3.11* 5.6 ) =

           = 299.495 K   =  26.3 degrees C

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