contestada

Wonton set his watch 8seconds behind, and it falls behind another 1 second everyday. How far behind is wontons watch if he last set it 26 days ago

Respuesta :

littlemisspotato03
to figure out the answer to this problem, we must first create a formula. the formula is going to be y=x+8.
-y is the amount of seconds behind
-x is the amount of days since it has last been set
-8 is how many seconds it's already behind

to solve, we need to fill in for x then solve the equation:
y=x+8
y=26+8
y=34

that means that wonton's watch is 34 seconds behind.

Otras preguntas