Respuesta :

blanchellite
3a-b=11 => b=3a-11
2a+3b=0
2a+3(3a-11)=0
2a+9a-33=0
11a=33
=>a=3
=> b=3*3-11=9-11=-2
3a−b=11;2a+3b=0

 Solve 3a−b=11 for b

3a−b+−3a=11+−3a(Add -3a)

−b=−3a+11

−b− 1 = −3a+11 / −1(Divide -1)

b=3a−11

Substitute (3a−11) for b in 2a+3b=0

2a+3b=0

2a+3(3a−11)=0

11a−33=0(Simplify)

11a−33+33=0+33(Add 33)

11a=33

11a/11 =33 / 11(Divide by 11)

a=3

 Substitute (3) for a in b=3a−11

b=3a−11

b=(3)(3)−11

b=−2(Simplify)

b=−2 and a=3