Answer:
Work done, [tex]W=1.03\times 10^6\ J[/tex]
Explanation:
It is given that,
Mass of the car, m = 950 kg
Distance up to the incline, d = 710 m
Angle of inclination of the car is 9 degrees.
When the car is push in the inclined path, the vertical component of the force will act on it such that the work done is given by :
[tex]W=mg\ sin\theta\times d[/tex]
[tex]W=950\times 9.8\times \ sin(9) \times 710[/tex]
[tex]W=1.03\times 10^6\ J[/tex]
So, the minimum work needed to push a car is [tex]1.03\times 10^6\ J[/tex]. Hence, this is the required solution.
