Answer:
Option A, C, F are the correct options.
Step-by-step explanation:
The given equation of line is [tex]y=\frac{1}{2}x[/tex]
Now we will plug in the values of points and validate the equation.
Option A. (2, 1)
[tex]y=\frac{1}{2}x[/tex]
[tex]1=\frac{2}{2}=1[/tex]
So this points lies on the given equation of line.
Option B. (3, 15)
[tex]15\neq \frac{3}{2}[/tex]
So the point is not on the line.
Option C. (4, 2)
[tex]2=\frac{4}{2}=2[/tex]
Point lies on the line.
Option D. (3, 6)
[tex]6\neq \frac{3}{2}[/tex]
Therefore point is not on the line.
Option E. (-2, 1)
[tex]1\neq \frac{-2}{2}[/tex]
Point does not lie on the line.
Option F. (-2, -1)
[tex]-1=\frac{-2}{2}=-1[/tex]
So this point lies on the line.
There are three points (2, 1), (4, 2) and (-2, -1) are on the line.
