a 75.00 g a sample of a substance is analyzed and found to consist of 32.73 g phosphorus and 42.7 g oxygen . calculate the percent composition of this substance.
the sum of the parts in this problem is slightly bigger than the total 32.73 + 42.7 = 75.43 Then the percentage composition is not going to be 100% exact but you can calculate some approximation in the following way
%= Part x 100/Total
phosphorous Part = 32.73 g oxygen Part = 42.7 g Total = 75.00 g
% phosphorous = 32.73 g x 100 / 75.00 g = 43.64% phosphorous
% oxygen = 42.7 g x 100 / 75.00 g = 56.93 % oxygen
