Respuesta :

7^5/4 would be the answer to the question I think you are asking
isyllus

Answer:

[tex]\sqrt[4]{7^5}=7^{\frac{5}{4}}[/tex]

Step-by-step explanation:

Given: "the fourth root of 7 to the fifth power"

First we write as radical form and then convert into rational fraction as per rule of exponent.

[tex]\text{the fourth root of 7 to the fifth power}=\sqrt[4]{7^5}[/tex]

[tex]\sqrt[n]{x^m}[/tex]

  • m, Power goes at numerator of rational exponent.
  • n , nth root goes at denominator of rational exponent.

So, [tex]\sqrt[n]{x^m}=x^{\frac{m}{n}}[/tex]

In the given radical, [tex]\sqrt[4]{7^5}[/tex]

m=5 and n=4

now, we write radical as a rational exponent.

[tex]\sqrt[4]{7^5}=7^{\frac{5}{4}}[/tex]

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