Respuesta :
The exponent graph for this question would be:
an= 3mm(1.25)^t
If the target length of the larvae is 9.16 mm, the time needed would be:
an= 3mm(1.25)^t
9.16 mm = 3mm(1.25)^t
3mm*3.053=3mm(1.25)^t
1.25^t= 3.053
1.25^t= 1.25^5
t=5
an= 3mm(1.25)^t
If the target length of the larvae is 9.16 mm, the time needed would be:
an= 3mm(1.25)^t
9.16 mm = 3mm(1.25)^t
3mm*3.053=3mm(1.25)^t
1.25^t= 3.053
1.25^t= 1.25^5
t=5