Respuesta :

texaschic101
y = mx + b
slope(m) = 1/4
(4,-8)....x = 4 and y = -8
now sub and find b, the y int
-8 = 1/4(4) + b
-8 = 1 + b
-8 - 1 = b
-9 = b
so ur equation is : y = 1/4x - 9....but we need it in standard form

y = 1/4x - 9
-1/4x + y = -9...multiply everything by -4
x - 4y = 36 <====

The equation, in standard form, of the line that passes through the point (4, -8) and has a slope of 1/4 is:

[tex]x=4y+36[/tex]

The point-slope equation of a line passing though the point (x₁, y₁) and which has a slope m is given as:

y  -  y₁   =  m(x  -  x₁)

The line described passes through the point (4, -8) and has a slope of 1/4.

That is:

m = 1/4

x₁  =  4

y₁  =  -8

Substitute these values into the point-slope form of the equation of a line

[tex]y-y_1=m(x-x_1)\\\\y-(-8)=\frac{1}{4}(x - 4)\\\\y+8=\frac{1}{4}x-1\\\\y= \frac{1}{4}x - 1 - 8\\\\y = \frac{1}{4}x-9\\\\x=4y+36[/tex]

Therefore, the equation, in standard form, of the line that passes through the point (4, -8) and has a slope of 1/4 is:

[tex]x=4y+36[/tex]

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