A rectangular pen is built with one side against a barn. if 300 m of fencing are used for the other three sides of the pen, what dimensions maximize the area of the pen?
let w= the length of the side perpendicular to the barn 300-2w= length of the side parallel to the barn A=w(300-2w) A=-2w^2+300w The formula for the w-value of maximum is: =-b/2a thus our value will be: 300/4 =75 and 300-2(75) =150 thus the dimensions to maximize the area is 75 by 150
