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Find the value(s) of x that make the equation true.

begin equation . . . 4 times x raised to the second power, plus 6 times x, plus 2 . . . equals 0 . . . end equation

A
x equals 1 or x equals, begin fraction . . . 1 over 2 . . . end fraction

Respuesta :


[tex]4 {x}^{2} + 6x + 2 = 0 \\ 2(2 {x}^{2} + 3x + 1) = 0 \\ 2(2x + 1)(x + 1) = 0 \\ x = - \frac{1}{2} \: or \: x = - 1[/tex]
Hope this helps. - M

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